Thread: Bash: Please explain ${var##*.}

i'm using bash find last part of string e.g. 'myfile.3' - found method works, don't know why!

should googling find out more this? reg exp or else?

code;

code:

var=my.test.file.23.45 echo $(( ${var##*.} + 1 ))

that returns '46', correct (i.e. 45+1) - need understand var##*. piece. how saying 'go end of string, part after '.', , return that'

look @ bottom of page, explains well.

http://mywiki.wooledge.org/bashguide/parameters

in order answer question should searching it's called parameter expansion.

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